Question

Calcule o quadrado e o cubo de um binômio.

Answer 1

Resposta:

Explicação passo-a-passo:

2.A) (4 + 1)²

       ⠀5²=25

B) (2 - y)²

2² - 4y + y²=

4 - 4y + y²

C) (3x + 2y²)³

(3x)³ + 3(3x)² × (2y²) + 3(3x) × (2x²)² + (2x²)³=

27x³ + 3 × 9x² × (2y²) + 9x × 4y⁴ + 8y⁶

⠀27x³ + 54x²y² + 36xy⁴ + 8y⁶

D) (4x² + 4w³)³=

(4x²)³ + 3(4x²)² × (4w³) + 3(4x²) × (4w³)² + (4w³)³

64x⁶ + 3 × 16x⁴ × 4w³ + 12x² × 16w⁶ + 64w⁹

⠀64x⁶ + 192x⁴w³ + 192x²w⁶ + 64w⁹

3.A) (_ + 3)² = a² + 6a + _

(a + 3)² = a² + 6a + 9

B) (2a + _)³ = 8a³ + _ + 54ab² + 27b³

(2a + 3b) = 8a³ + 36a²b + 54ab² + 27b³

C) (3a² - 2b)² = _ - 12a²b + _

⠀(3a² - 2b)² = 9a⁴ - 12a²b + 4b²

Answer 2

Resposta:

2.A) (4 + 1)²

      ⠀5²=25

B) (2 - y)²

2² - 4y + y²=

4 - 4y + y²

C) (3x + 2y²)³

(3x)³ + 3(3x)² × (2y²) + 3(3x) × (2x²)² + (2x²)³=

27x³ + 3 × 9x² × (2y²) + 9x × 4y⁴ + 8y⁶

⠀27x³ + 54x²y² + 36xy⁴ + 8y⁶

D) (4x² + 4w³)³=

(4x²)³ + 3(4x²)² × (4w³) + 3(4x²) × (4w³)² + (4w³)³

64x⁶ + 3 × 16x⁴ × 4w³ + 12x² × 16w⁶ + 64w⁹

⠀64x⁶ + 192x⁴w³ + 192x²w⁶ + 64w⁹

3.A) (_ + 3)² = a² + 6a + _

(a + 3)² = a² + 6a + 9

B) (2a + _)³ = 8a³ + _ + 54ab² + 27b³

(2a + 3b) = 8a³ + 36a²b + 54ab² + 27b³

C) (3a² - 2b)² = _ - 12a²b + _

⠀(3a² - 2b)² = 9a⁴ - 12a²b + 4b²

Explicação passo-a-passo: