Question

econtre as raizes da equação de segundo grau x² -3x +2=0

Answer 1

Explicação passo-a-passo:

$\sf x^2-3x+2=0$

$\sf \Delta=(-3)^2-4\cdot1\cdot2$

$\sf \Delta=9+8$

$\sf \Delta=1$

$\sf x=\dfrac{-(-3)\pm\sqrt{1}}{2\cdot1}=\dfrac{3\pm1}{2}$

$\sf x'=\dfrac{3+1}{2}~\longrightarrow~x'=\dfrac{4}{2}~\longrightarrow~x'=2$

$\sf x"=\dfrac{3-1}{2}~\longrightarrow~x"=\dfrac{2}{2}~\longrightarrow~x"=1$

As raízes são $\sf 1$ e $\sf 2$

Answer 2

Resposta:

S={2,1}

Explicação passo-a-passo:

Δ=(-3)²-4.1.2

Δ=9+(-4).2

Δ=9+(-8)

Δ=1

×1=-(-3)+√1/(2.1)

×1=3+√1/2

×1=3+1/2

×1=4/2

×1=2

×2=-(-3)-√1/(2.1)

×2=3-√1/2

×2=3-1/2

×2=2/2

×2=1