Question

Me ajudem urgente!!! limite x->2 ((4x^3-2x^2-6)^3) / ((-x^2+3x+4)^3)

Answer 1

Resposta:

$lim = \frac{(4x^3-2x^2-6)^3}{(x^2+3x+4)^3} = \frac{(4.2^3-2.2^2-6)^3}{(2^2+3.2+4)^3} = \frac{18^3}{14^3} =\frac{5832}{2744} = 2,1254$