Question

**ME AJUDEM POR FAVOR*

Quantos mols correspondem a 9,03x10²⁴ íons de Al+³? *

9,03 mols.

1,5 mols.

0,15 mols.

15 mols

150 mols.

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Answer 1

1 mol - 6,02 x 10²³

x       -  9,03x10²⁴

6,02 x 10²³ * x = 9,03x10²⁴ * 1

x = (9,03x10²⁴)/6,02 x 10²³

x = 15 mols