Question

URGENTEEE pfv teorema de Pitágoras

Answer 1

Resposta:

${(5 \sqrt{2} )}^{2} = {(3 \sqrt{2}) }^{2} + {x}^{2}$

$25 \times 2 = 9 \times 2 + {x}^{2}$

$50 - 18 = {x}^{2}$

${x}^{2} = 32 = > x = \sqrt{32}$

$x = 4 \sqrt{2}$

b)

${(2x + 5)}^{2}= {(3x - 10})^{2} + {(x + 9)}^{2}$