Question

sendo f(x) = -2/3x + 18, calcule:
a) f(27)
b) f(0)
c) f(-3)

Answer 1

$f(x) = - \frac{2}{3}x+18 \\ \\ a) \\ f(27)= - \frac{2}{3}.27+18 \\ \\ f(27)=-2.9+18 \\ \\ f(27)=-18+18=0 \\ \\ \\ b) \\ f(0)=- \frac{2}{3}.0+18=18 \\ \\ \\ c) \\ f(-3)= -\frac{2}{3}(-3)+18 \\ \\ f(-3)=2+18=20$