Question

Dados os pontos A (5, -2), B (3, 0), C (1, -5) e D (-8, -1), determine as coordenadas dos pontos médios do segmentos:

a) AB

 

b)AD

 

c)BD

 

d) AC

Answer 1

$Pm = (\frac{x1 + x2}{2} ,\frac{y1 + y2}{2})\\\\ Pm = (\frac{5 + 3}{2} ,\frac{-2 + 0}{2})\\\\ Pm(AB) = (4 ,-1)\\\\ Pm = (\frac{x1 + x2}{2} ,\frac{y1 + y2}{2})\\\\ Pm = (\frac{5 -8}{2} ,\frac{-2-1}{2})\\\\ Pm(AD) = (-\frac{3}{2} ,-\frac{3}{2})\\\\ Pm = (\frac{x1 + x2}{2} ,\frac{y1 + y2}{2})\\\\ Pm = (\frac{3-8}{2} ,\frac{0 -1}{2})\\\\ Pm(BD) = (-\frac{5}{2} ,-\frac{1}{2})$
$Pm = (\frac{x1 + x2}{2} ,\frac{y1 + y2}{2} )\\\\ Pm = (\frac{5 + 1}{2} ,\frac{-2 - 5}{2} )\\\\ Pm(AC) = (3 ,-\frac{7}{2} )$

Answer 2

Resposta:

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