Question

Segunda parte da minha outra pergunta!!!

Answer 1

Resposta:

d)

$a=m+n\\a=6\\\\h^2=2*4\\h^2=8\\h=2\sqrt{2}$

$b^2=4^2+(2\sqrt{2})^2\\b^2=16+8\\b^2=24\\b=\sqrt{24}\\b=2\sqrt{6}$

$c^2=2^2+(2\sqrt{2})^2\\c^2=4+8\\c^2=12\\c=\sqrt{12}\\b=2\sqrt{3}$

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2)

$6^2=4^2+h^2\\36=16+h^2\\20 = h^2\\h=\sqrt{20}\\h=2\sqrt{5}$

$h^2=m*n\\20=4n\\n=5$

$a = m+n\\a= 4+5\\a=9$

$c^2=h^2+n^2\\c^2=20+25\\c^2=45\\c=\sqrt{45}\\c=3\sqrt{5}$

$Área = \frac{b*h}{2} = \frac{9*2\sqrt{5} }{2} = 9\sqrt{5}$

$Perimetro = 6+9+3\sqrt{5} = 15+3\sqrt{5}$

3)

$a=m+n\\20=7+n\\n=13$

$h^2 = m*n\\h^2 = 13*7\\h^2 = 91\\h = \sqrt{91}$

$b^2 = a*m\\b^2 = 20*7\\b^2 = 140\\b = \sqrt{140}\\b = 2\sqrt{35}$

$c^2 = a*n\\c^2 = 20*13\\c^2 = 260\\c = \sqrt{260}\\c = 2\sqrt{65}$

$Perimetro = 20 + 2\sqrt{65} + 2\sqrt{35}$

$Area = \frac{20*\sqrt{91}}{2} = 10\sqrt{91}$