Question

calcule o valor de x nos triangulos retangulos​

Answer 1

Resposta:

$a) {x}^{2} = {8}^{2} + {6}^{2} \\ \: \: {x}^{2} = 64 + 36 \\ \: \: {x}^{2} = 100 \\ \: \: x = \sqrt{100} = 10. \\ \\ b) {5}^{2} = {x}^{2} + {4}^{2} \\ \: 25 = {x}^{2} + 16 \\ \: \: - {x}^{2} = 16 - 25 \\ \: \: - {x}^{2} = - 9 \: \times ( - 1) \\ \: \: {x}^{2} = 9 \\ \: \: x = \sqrt{9} \\ \: \: x = 3.$