Question

4 — Calcule:
a) 3–{2³+(11–15)–[5+(-3+1)⁴]+8}=
b) [–1+(22–5.6)³]÷(-5+2)²+1=
c) [–(24–8).2–24]÷[22–(-3+2)¹³]=

Me ajudem prgvr

Answer 1

a)3 - {2 + (11 - 15) - [5 + (- 3 + 1)] + 8} =

3 - {2 + (- 4) - [5 + (- 2)] + 8} =

3 - {2 - 4 - [5 - 2] + 8} =

3 - {2 - 4 - 3 + 8} =

3 - {2 - 7 + 8} =

3 - {- 5 + 8} =

3 - 3 =

0

b) [ - 1 + (2²  – 5 · 6)] ÷ (- 5 + 2) + 1

= [ - 1 + (4 - 30)] : ( - 3) + 1

= [ - 1 + ( - 26) ] : ( - 3) +

= [ - 1 - 26] : ( - 3) + 1

= [- 27 ] : ( - 3) + 1

= 9 + 1

= 10

c)[-(24-8)×2-24]÷[22-(-3+2)]

[-(16)×2-24]÷[22-(-1)]

[-32-24]÷{22+1]

[-56]÷[23]

=-2,4

Espero ter ajudado, bons estudos!