Question

5.Calcule os vértices da função f(x)= x²+6x+2

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Answer 1

Resposta:

f(x)= x²+6x+2

x² + 6x + 2 = 0

a = 1

b = 6

c = 2

b = + 6

c = + 2

$Vx =\frac{-b}{2a} = \frac{-6}{2*2} =\frac{- 6}{4} =\frac{-3}{2}$

Δ = b² -4ac = 6² - 4 *2 = 36 - 8 =  28

$Vy = \frac{-\Delta}{4a} = \frac{-28}{4 *1} = \frac{-28}{4} = - 7$