Question

resolva as expressões numéricas
a) 7-(1+3)=

b)25+{12+[2-(8-6)+2]}=

e)10-(2+5)+4=

f) {[(18-3)+(7+5)-2]+5}-12=

g)28+[50-(24-2)-10=

h) 38-{20-[22-(5+3)+(7-4+1)]}
​

Answer 1

Explicação passo-a-passo:

$a)\: 7-(1+3)$

$7-1-3$

$3$.

$b)\: 25+\{12+[1-(8-6)+2]\}$

$25+\{12+[2-(2)+2]\}$

$25+\{12+1\}$

$25+13$

$38$.

$e)\: 10-(2+5)+4\\10-7+4\\3+4\\ 7.$

$f)\: \{[(18-3)+(7+5)-2]+5\}-12\\\{[(15)+(12)-2]+5\}-12\\\{[25]+5\}-12\\30-12\\18.$

$g)\: 28+[50-(24-2)-10]\\28+[50-(22)-10]\\28+[28-10]\\ 46.$

$h)\: 38-{20-[22-(5+3)+(7-4+1)]}38-{20-[22-(8)+(4)]}\\38-{20-[18]}\\38-2\\ 36.$