Question

dada a funçao f(x)= -3x²+x+2 determine as raízes

Answer 1

Resposta:

Explicação passo-a-passo:

f(x)= -3x²+x+2

a = -3

b = 1

c = 2

$x = \frac{-(b) +- \sqrt{(b)^{2} - 4 * a * c} }{2*a}\\\\x = \frac{-(1) +- \sqrt{(1)^{2} - 4 * -3 * 2} }{2*-3}\\\\x = \frac{-1+-\sqrt{1+24} }{-6}\\\\x = \frac{-1+-\sqrt{25} }{-6}\\\\x = \frac{-1+-5}{-6}\\\\x' = \frac{-1+5}{-6}=\frac{4}{-6}=\frac{2}{-3} \\\\x'' = \frac{-1-5}{-6}=\frac{-6}{-6} =1$

Answer 2

Resposta:

X1=-2/3 ,x2 = 1

Explicação passo-a-passo:

0 =-3 X sobre 2 +x + 2

-3x sobre 2 +x+2 =0

3 x sobre 2 -x-2=0

3 x sobre 2 +2x+3x-2=0

x×(3x+2) - (3x-2)=0

(3x +2) ×(x-1)=0

3 x +2 =0

x-1=0

x= -2/3

x= 1

X1=-2/3 ,x2 = 1