Question

sendo f(x)=Ax+B onde f(20)=48 f(5)=18 quando m=f (15) + f(9) e :





mim ajudaaaaa​

Answer 1

Resposta:

64

Explicação passo-a-passo:

$f(x)=ax+b\\f(20)=48\\\\a(20)+b=48\\b=48-20a\\\\f(5)=18\\a(5)+b=18\\5a+(48-20a)=18\\-15a=18-48\\-15a=-30\\a=\frac{-30}{-15} \\a=2\\\\b=48-20a\\b=48-20(2)\\b=48-40\\b=8\\\\f(15)=2(15)+8\\f(15)=30+8\\f(15)=38\\\\f(9)=2(9)+8\\f(9)=18+8\\f(9)=26\\\\f(15)+f(9)\\38+26\\64$