Question

[[[[[[[[[[alguém pode me ajudar aquiii? estou com muita dificuldade pfvrrrr]]]]]]]]]] a) 12/6-3/8= b) 4/3-1/6= c) 7/4-8/9= d) 10/5-3/6= e) 5/4-2/6-4/5=

Answer 1

a)  $\frac{12}{6}-\frac{3}{8}=\frac{4}{2}-\frac{3}{8}=\frac{4\times4}{2\times4}-\frac{3}{8}=\frac{16}{8}-\frac{3}{8}=\frac{16-3}{8}=\frac{13}{8}$

b)  $\frac{4}{3}-\frac{1}{6}=\frac{4\times2}{3\times2}-\frac{1}{6}=\frac{8}{6}-\frac{1}{6}=\frac{8-1}{6}=\frac{7}{6}$

c)  $\frac{7}{4}-\frac{8}{9}=\frac{7\times9}{4\times9}-\frac{8\times4}{9\times4}=\frac{63}{36}-\frac{32}{36}=\frac{63-32}{36}=\frac{31}{36}$

d)  $\frac{10}{5}-\frac{3}{6}=2-\frac{1}{2}=\frac{4}{2}-\frac{1}{2}=\frac{4-1}{2}=\frac{3}{2}$

e)  $\frac{5}{4}-\frac{2}{6}-\frac{4}{5}=\frac{5\times15}{4\times15}-\frac{2\times10}{6\times10}-\frac{4\times12}{5\times12}=\frac{75}{60}-\frac{20}{60}-\frac{48}{60}=\frac{75-20-48}{60}=\frac{75-20-48}{60}=\frac{7}{60}$