Question

Resolva a equação e encontre o valor de x que satisfaça essa igualdade

Answer 1

Explicação passo-a-passo:

$\sf x\cdot x-5\cdot x=-6$

$\sf x^2-5x+6=0$

$\sf \Delta=(-5)^2-4\cdot1\cdot6$

$\sf \Delta=25-24$

$\sf \Delta=1$

$\sf x=\dfrac{-(-5)\pm\sqrt{1}}{2\cdot1}=\dfrac{5\pm1}{2}$

$\sf x'=\dfrac{5+1}{2}~\rightarrow~x'=\dfrac{6}{2}~\rightarrow~x'=3$

$\sf x"=\dfrac{5-1}{2}~\rightarrow~x"=\dfrac{4}{2}~\rightarrow~x"=2$

$\sf S=\{2,3\}$

Answer 2

Explicação passo-a-passo:

$\blue {{ _{\heartsuit} } \heartsuit_{\heartsuit} } \: \: \mathsf {OI, TUDO \: \: J\acute{O}IA \: ? \: \:\blue {{ _{\heartsuit} } \heartsuit_{\heartsuit} } }$

$\mathtt{x \times x \times - 5 \times x = - 6 } \\ \mathtt{ {x}^{2} - 5x = - 6 } \\ \mathtt{ {x}^{2} - 5x + 6 = 0} \\ \mathtt{ {x}^{2} - 2x - 3x + 6 = 0 } \\ \mathtt{x(x - 2) - 3(x - 2) = 0} \\ \mathtt{(x - 2) \times (x - 3) = 0} \\ \mathtt{x - 2 = 0} \\ \mathtt{x - 3 = 0} \\ \mathtt{x = 2} \\ \mathtt{x = 3} \\ \huge\red{\mathtt{s = (2,3)}}$