Question

Quanto mede, aproximadamente, o lado AB da figura expressa abaixo?

Answer 1

$\mathsf{\overline{AB}^2=6^2+5^2-2\cdot6\cdot5\cdot cos(120^{\circ})}\\\mathsf{\overline{AB}^2=36+25-2\cdot6\cdot5\cdot\left(-\dfrac{1}{2}\right)}\\\mathsf{\overline{AB}^2=61+30}\\\mathsf{\overline{AB}^2=91}\\\mathsf{\overline{AB}=\sqrt{91}}\\\huge\boxed{\boxed{\boxed{\boxed{\mathsf{\overline{AB}\approx9,53}}}}}\\\huge\boxed{\boxed{\boxed{\boxed{\mathsf{\maltese~~alternativa~~b}}}}}$

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