• Matéria: Matemática
  • Autor: kittyfigueiredobrasi
  • Perguntado 6 anos atrás

Resolva: x+y=6 x-y=8 Com prova real se conseguirem!!

Respostas

respondido por: ShinyComet
2

    \left\{\begin{array}{ll}x+y=6\\x-y=8\end{array}\right\Leftrightarrow

\Leftrightarrow\left\{\begin{array}{ll}y=6-x\\x-y=8\end{array}\right\Leftrightarrow

\Leftrightarrow\left\{\begin{array}{ll}y=6-x\\x-(6-x)=8\end{array}\right\Leftrightarrow

\Leftrightarrow\left\{\begin{array}{ll}y=6-x\\x-6+x=8\end{array}\right\Leftrightarrow

\Leftrightarrow\left\{\begin{array}{ll}y=6-x\\x+x=8+6\end{array}\right\Leftrightarrow

\Leftrightarrow\left\{\begin{array}{ll}y=6-x\\2x=14\end{array}\right\Leftrightarrow

\Leftrightarrow\left\{\begin{array}{ll}y=6-x\\x=\frac{14}{2}\end{array}\right\Leftrightarrow

\Leftrightarrow\left\{\begin{array}{ll}y=6-x\\x=7\end{array}\right\Leftrightarrow

\Leftrightarrow\left\{\begin{array}{ll}y=6-7\\x=7\end{array}\right\Leftrightarrow

\Leftrightarrow\left\{\begin{array}{ll}y=-1\\x=7\end{array}\right

  Confirmação  

Seja  x=7  e  y=-1 :

    \left\{\begin{array}{ll}x+y=6\\x-y=8\end{array}\right\Leftrightarrow

\Leftrightarrow\left\{\begin{array}{ll}7+(-1)=6\\7-(-1)=8\end{array}\right\Leftrightarrow

\Leftrightarrow\left\{\begin{array}{ll}7-1=6\\7+1=8\end{array}\right\Leftrightarrow

\Leftrightarrow\left\{\begin{array}{ll}6=6\;\;\;\;(Verdade)\\8=8\;\;\;\;(Verdade)\end{array}\right

Resposta:  (x\;;\;y)=(7\;;\;-1)


kittyfigueiredobrasi: Obrigada.
ShinyComet: De nada
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