Question

6x²+4x-2=0 equaçao de segundo grau usando baskara

Answer 1

Explicação passo-a-passo:

$\sf 6x^2+4x-2=0$

$\sf \Delta=4^2-4\cdot6\cdot(-2)$

$\sf \Delta=16+48$

$\sf \Delta=64$

$\sf x=\dfrac{-4\pm\sqrt{64}}{2\cdot6}=\dfrac{-4\pm8}{12}$

$\sf x'=\dfrac{-4+8}{12}~\rightarrow~x'=\dfrac{4}{12}~\rightarrow~x'=\dfrac{1}{3}$

$\sf x"=\dfrac{-4-8}{12}~\rightarrow~x"=\dfrac{-12}{12}~\rightarrow~x"-1$

$\sf S=\left\{-1,\dfrac{1}{3}\right\}$

Answer 2

Resposta:

solução ( -1 e 1/3)

Explicação passo-a-passo:

6x²+4x-2=0

Δ=4²-4·6·-2

Δ=16+48

Δ=64

x= -4±√64/12

x= -4±8/12

x´1= -4-8/12

Resposta⇒x´1= -1

x´2= -4+8/12

Resposta⇒x´2=1/3