• Matéria: Matemática
  • Autor: casssantannaa15
  • Perguntado 6 anos atrás

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Anexos:

Respostas

respondido por: MathRevan
0

Resposta:

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Explicação passo-a-passo:

2A = \left[\begin{array}{ccc}(-1).2&0.2\\2.2&1.2\end{array}\right]  = \left[\begin{array}{ccc}-2&0\\4&2\end{array}\right]

\frac{1}{2}. B=  \frac{B}{2} = \left[\begin{array}{ccc}\frac{4}{2}&\frac{2}{2}\\\frac{1}{2}&\frac{0}{2}\end{array}\right] = \left[\begin{array}{ccc}2&1\\\frac{1}{2}&0\end{array}\right]

Então, 2A - \frac{1}{2}.B = \left[\begin{array}{ccc}-2&0\\4&2\end{array}\right] - \left[\begin{array}{ccc}2&1\\\frac{1}{2}&0\end{array}\right] = \left[\begin{array}{ccc}-4&-1\\\frac{7}{2}&2\end{array}\right]

Alternativa A.

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