• Matéria: Matemática
  • Autor: lidianerodrigues015
  • Perguntado 6 anos atrás

Racionalizar os Denominadores​

Anexos:

Respostas

respondido por: CyberKirito
2

\sf{\dfrac{\sqrt{7}+\sqrt{3}}{\sqrt{7}-\sqrt{3}}=\dfrac{(\sqrt{7}+\sqrt{3})}{(\sqrt{7}-\sqrt{3})}\cdot\dfrac{(\sqrt{7}+\sqrt{3})}{(\sqrt{7}+\sqrt{3})}}\\\sf{\dfrac{7+2\cdot\sqrt{21}+3}{7-3}=\dfrac{10+2\sqrt{21}}{4}=\dfrac{\diagup\!\!\!\! 2\cdot(5+\sqrt{21})}{\diagup\!\!\!\!4}}\\\large\huge\boxed{\boxed{\boxed{\boxed{\sf{\dfrac{5+\sqrt{21}}{2}}}}}}

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