Question

t elevado a 2+6t+8=0​

Answer 1

Olá!

$delta = {b}^{2} - 4ac$

$delta = {6}^{2} - 4 \times 1 \times 8$

$delta = 36 - 32$

$delta = 4$

$x = \frac{ - b + - \sqrt{ delta} }{2 \times a}$

$x = \frac{ - (6) + - { \sqrt{4} } }{2 \times 1}$

$x = \frac{-6 + - 2}{2}$

$x1 = \frac{-6 + 2}{2} = \frac{-4}{2} = -2$

$x2 = \frac{-6 - 2}{2} = \frac{-8}{2} = -4$