• Matéria: Matemática
  • Autor: jociscleidibezerra
  • Perguntado 6 anos atrás

Determine :::::(A)::::::(B)::::::(C):::::::(D)

Anexos:

Respostas

respondido por: Anônimo
2

Explicação passo-a-passo:

a)

\sf A=(-1-1)\cdot\left(-2+\dfrac{5}{4}\right)-\dfrac{1}{2}

\sf A=(-2)\cdot\left(\dfrac{-8+5}{4}\right)-\dfrac{1}{2}

\sf A=(-2)\cdot\left(-\dfrac{3}{4}\right)-\dfrac{1}{2}

\sf A=\dfrac{6}{4}-\dfrac{1}{2}

\sf A=\dfrac{3}{2}-\dfrac{1}{2}

\sf A=\dfrac{2}{2}

\sf A=1

b)

\sf B=\dfrac{-\dfrac{5}{8}}{+\dfrac{5}{12}}

\sf B=-\dfrac{5}{8}\cdot\dfrac{12}{5}

\sf B=-\dfrac{60}{40}

\sf B=-\dfrac{3}{2}

c)

\sf 1-A+B=1-1-\dfrac{3}{2}

\sf 1-A+B=-\dfrac{3}{2}

d)

\sf (A+B)^2=\left(1-\dfrac{3}{2}\right)^2

\sf (A+B)^2=\left(\dfrac{2-3}{2}\right)^2

\sf (A+B)^2=\left(-\dfrac{1}{2}\right)^2

\sf (A+B)^2=\dfrac{1}{4}

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