Question

Resolva as equações abaixo utilizando a fórmula
de Bháskara.
a) x2 -7x +6 = 0

Answer 1

Resposta:

x' = 6 e x'' = 1

Explicação passo-a-passo:

x² -7x +6 = 0

Δ = (-7)² - 4 . 1 . 6

Δ = 49 - 24

Δ = 25

x = -(-7) ± $\sqrt{}$Δ / 2 . 1

x = 7 ± 5 / 2

x' = 7 + 5 / 2

x' = 12 / 2

x' = 6

x'' = 7 - 5 / 2

x'' = 2 / 2

x'' = 1

Answer 2

$\sf{x^2-7x+6=0}\\\sf{a=1~~b=-7~~c=6}\\\sf{\Delta=b^2-4ac}\\\sf{\Delta=(-7)^2-4\cdot1\cdot6}\\\sf{\Delta=49-24}\\\sf{\Delta=25}\\\sf{x=\dfrac{-b\pm\sqrt{\Delta}}{2a}</p><p>}\\\sf{x=\dfrac{-(-7)\pm\sqrt{25}}{2\cdot1}}\\\sf{x=\dfrac{7\pm5}{2}}\begin{cases}\sf{x_1=\dfrac{7+5}{2}=\dfrac{12}{2}=6}\\\sf{x_2=\dfrac{7-5}{2}=\dfrac{2}{2}=1}\end{cases}$