Question

logaritimo de 0,00064 na bse 5

Answer 1

lembrando que 
log (a.b) = log a + log b 
log (a^m) = m log a 
log5 (5) = 1 
temos: 

log5 (0,000064) = 
log5 [64 x 10^(-6)] = 
log5 (64) + log5 [10^(-6)] = 
log5 (2^6) -6 log5 (10) = 
6 log5 (2) -6 log5 (2 . 5) = 
6 log5 (2) -6 log5 (2) - 6 log5 (5) = 
-6 log5 (5) = 
-6