Question

Racionalize o denominador: $\frac{3}{ \sqrt[3]{6^{7} } }$

Answer 1

$\frac{3}{ \sqrt[3]{ 6^{7}}} = \frac{3}{ \sqrt[3]{ 6^{3}.6^{3}.6}} = \frac{3}{ 6 . 6 . \sqrt[]{ 6}} = \frac{3}{ 36\sqrt[3]{ 6}} = \frac{1}{ 12\sqrt[3]{ 6}} = \\ \frac{1}{ 12\sqrt[3]{ 6}} . \frac{(\sqrt[3]{ 6})^2}{( \sqrt[3]{ 6})^2} = \frac{(\sqrt[3]{ 6})^2}{12( \sqrt[3]{ 6})^3} = \frac{(\sqrt[3]{ 6})^2}{12 . 6} = \frac{(\sqrt[3]{ 6})^2}{36}$