Question

quais são os vértices de x2+5x+4 e x2-10+25?

Answer 1

x² +5x +4

delta = (5²) - 4.1.4

25 - 16

delta = 9

x = - 5 + - raiz (9) / 2 *1

x= -5 +- 3 /2

x¹= -5 -3 /2

x¹= -4

x²=-5 +3/2

x²=-1

delta = (-10²) - 4*1*25

100 - 100

0

x = -2 +- raiz 0 / 2

x¹ e x² = -1