Question

Alguém pode me ajudar por favor?​

Answer 1

Explicação passo-a-passo:

a)

$\sqrt{8}\times \sqrt{6} =\sqrt{8\times6} =\sqrt{48} =\sqrt{16\times3} =\sqrt{16}\times\sqrt{3} =4\sqrt{3}$

b)

$\sqrt{2}\times \sqrt{27} =\sqrt{2\times27} =\sqrt{54} =\sqrt{9\times6} =\sqrt{9}\times\sqrt{6} =3\sqrt{6}$

c)

$\sqrt{42}\times \sqrt{28} =\sqrt{42\times28} =\sqrt{1176} =\sqrt{196\times6} =\sqrt{196}\times\sqrt{6} =14\sqrt{6}$

d)

$2\sqrt{10}\times 5\sqrt{30} =10\sqrt{10\times30} =10\sqrt{300} =10\sqrt{100\times3} \\\\=10\times\sqrt{100}\times\sqrt{3}=10\times10\times\sqrt{6}=100\sqrt{6}$

e)

$\sqrt{8}\times \sqrt{12} =\sqrt{8\times12} =\sqrt{96} =\sqrt{16\times6} =\sqrt{16}\times\sqrt{6} =4\sqrt{6}$