Question

3- Racionalize o denominador da
fração:
​

Answer 1

Resposta:

a) 1/√2

1*√2/√2*√2

√2/√4

√2/2

b) 2/raiz de 3=2-raiz de 3/raiz de 3 ao quadrado=2-raiz de 3/3. concluindo que 2-raiz de 3/3

c)   4    =     4√2    ==>  4√2  ==> √2

2√2       2√2√2           2.2

D)

Answer 2

Oie, Td Bom?!

a)

$= \frac{1}{ \sqrt{2} }$

$= \frac{1}{ \sqrt{2} } \: . \: \frac{ \sqrt{2} }{ \sqrt{2} }$

$= \frac{1 \sqrt{2} }{ \sqrt{2} \sqrt{2} }$

$= \frac{ \sqrt{2} }{2}$

b)

$= \frac{2}{ \sqrt{3} }$

$= \frac{2}{ \sqrt{3} } \: . \: \frac{ \sqrt{3} }{ \sqrt{3} }$

$= \frac{2 \sqrt{3} }{ \sqrt{3} \sqrt{3} }$

$= \frac{2 \sqrt{3} }{ 3}$

c)

$= \frac{4}{2 \sqrt{2} }$

$= \frac{2}{ \sqrt{2} }$

$= \frac{2}{ \sqrt{2} } \: . \: \frac{ \sqrt{2} }{ \sqrt{2} }$

$= \frac{2 \sqrt{2} }{ \sqrt{2} \sqrt{2} }$

$= \frac{2 \sqrt{2} }{2}$

$= \sqrt{2}$

d)

$= \frac{2 \sqrt{5} }{5 \sqrt{2} }$

$= \frac{2 \sqrt{5} }{5 \sqrt{2} } \: . \: \frac{ \sqrt{2} }{ \sqrt{2} }$

$= \frac{2 \sqrt{5} \sqrt{2} }{5 \sqrt{2} \sqrt{2} }$

$= \frac{2 \sqrt{10} }{5 \: . \: 2}$

$= \frac{2 \sqrt{10} }{10}$

$= \frac{ \sqrt{10} }{5}$

Att. Makaveli1996