Question

Me ajudem como resolvo? x²+25x=0

Answer 1

x² + 25x + 0 =0

a = 1
b = 25
c = 0

Δ= b² - 4.a.c  
Δ = 25² - 4.1.0
Δ = 625

x1 = -b + √Δ / 2.a

x1 = - 25 + √ 625 / 2.1
x1 = - 25 + 25 / 2  =  0


x2 = -b - √Δ /2a


x2 = - 25 - 25 / 2   ~>  -50 / 2 =  - 25


S { 0 , -25 }

BOA SORTE E ESTUDE!

Answer 2

A=1 b=25 c=0

Delta=25²-4.1.0
Delta=625

$X= \frac{-25+- \sqrt{625} }{2.1}$
$X= \frac{0}{2}$

X¹=$\frac{-25+25}{2}$ = 0
X²=$\frac{-25-25}{2}$ =$\frac{-50}{2}$ = -25
S={0, -25}