Question

SEJAM p1(x) = x³ - 4x² + 5x – 4 e p2(x) = 3x² - 4x + 3


CALCULE.

A) p1(x) + p2(x)

B) 2p1(x) – p2(x)

C) 3p1(x) + 2p2(x)
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Answer 1

a) p1(x) + p2(x) = (x^3 -4x^2 +5x -4) + (3x^2 -4x +3) = x^3 -x^2 +x -1

b) 2p1(x) - p2(x) = 2(x^3 - 4x^2 +5x -4) - (3x^2 -4x +3). = 2x^3 -8x^2 +10x -8 -3x^2 +4x -3 = 2x^3 -11x^2 +14x -11

c) 3p1(x) + 2p2(x) = 3(x^3 -4x^2 +5x -4) + 2(3x^2 -4x +3) = 3x^3 -12x^2 +15x -12 +6x^2 -8x +6 = 3x^3 -6x^2 +7x -6