Question

C) (x+1)^2 - (2x+3)^2=0

Answer 1

Explicação passo-a-passo:

${(x + 1)}^{2} - {(2x + 3)}^{2} = 0$

${x}^{2} + 2 x + 1 - ( {4x}^{2} + 12x + 9) = 0$

${x}^{2} + 2x + 1 - {4x}^{2} - 12x - 9 = 0$

${ - 3x}^{2} - 10x - 8 = 0$

${3x}^{2} + 10x + 8 = 0$

${3x}^{2} + 6x + 4x + 8 = 0$

$3x \times (x + 2) + 4(x + 2) = 0$

$(x + 2) \times (3x + 4) = 0$

$x + 2 = 0$

$3x + 4 = 0$

$x = - 2$

$x = - \frac{4}{3}$

$x_{1} = - 2, x_{2} = - \frac{4}{3}$