• Matéria: Matemática
  • Autor: alexhla
  • Perguntado 9 anos atrás

Função Exponencial básico.

a) ( \frac{ 1 }{2})^{-2} + ( \frac{ 1 }{3})^{-1}

b) [( -\frac{ 5 }{3})^{-1} + ( \frac{ 5 }{2})^{-1}]^{-1}ex]

c) [ 3^{-1} - (-3)^{-1}]^{-1}

d) 6. ( \frac{2}{3})^{2} + 4. (- \frac{3}{2})^{-2}

Respostas

respondido por: MATHSPHIS
1
a)
( \frac{ 1 }{2})^{-2} + ( \frac{ 1 }{3})^{-1}=\\
\\2^2+3=4+3=7

b)
[( -\frac{ 5 }{3})^{-1} + ( \frac{ 5 }{2})^{-1}]^{-1}=\\
\\
(-\frac{3}{5} +\frac{2}{5})^{-1}=(-\frac{1}{5})^{-1}=-5

c)
 [ 3^{-1} - (-3)^{-1}]^{-1} =\\
\\
(\frac{1}{3}-(-\frac{1}{3}))^{-1}=\\
\\
(\frac{1}<br />{3}+\frac{1}{3})^{-1}=\\
\\
(\frac{2}{3})^{-1}=\frac{3}{2}

d)
6. ( \frac{2}{3})^{2} + 4. (- \frac{3}{2})^{-2} =\\
\\
6.\frac{4}{9}+4(-\frac{4}{9})=\\
\\
\frac{24}{9}-\frac{16}{9}=\frac{8}{9}
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