• Matéria: Matemática
  • Autor: kermit429
  • Perguntado 6 anos atrás

1) calcule: A) (a^5)²= b) (-2x^4)²= C) (-5y³)³= D) (-10a² b)²= e) (-3x² y)^4= f) (-1/5 m² n)²= g) (0,5a b)²= h) (-a m^5 x³)^4 i) (2/3 x³ y²)^4 j) (a² c³)^7

Anexos:

Respostas

respondido por: Makaveli1996
6

Oie, Td Bom?!

A)

 = (a {}^{5} ) {}^{2}

 = a {}^{5  \: . \: 2}

 = a {}^{10}

B)

 = ( - 2x {}^{4} ) {}^{2}

 = ( - 2) {}^{2}  \: . \: (x {}^{4} ) {}^{2}

 = 2 {}^{2}  \: . \: x {}^{4 \: . \: 2}

 = 4x {}^{8}

C)

 = ( - 5y {}^{3} ) {}^{3}

 = ( - 5) {}^{3}  \: . \: (y {}^{3} ) {}^{3}

 =  - 5 {}^{3}  \: . \: y {}^{3 \: . \: 3}

 =  - 125y {}^{9}

D)

 = ( - 10a {}^{2} b) {}^{2}

 =  (- 10) {}^{2}  \: . \: (a {}^{2} ) {}^{2}  \: . \: b {}^{2}

 = 10 {}^{2}  \: . \: a {}^{2 \: . \: 2}  \: . \: b {}^{2}

 = 100a {}^{4} b {}^{2}

E)

 = ( - 3x {}^{2} y ){}^{4}

 = ( -  3) {}^{4}  \: . \: (x {}^{2} ) {}^{4}  \: . \: y {}^{4}

 =  - 3 {}^{4}  \: . \: x {}^{2 \: . \: 4}  \: . \: y {}^{4}

 = 81x {}^{8} y {}^{4}

F)

 = ( -  \frac{1}{5} m {}^{2} n) {}^{2}

 = ( -  \frac{1}{5} ) {}^{2}  \: . \: (m {}^{2} ) {}^{2}  \: . \: n {}^{2}

 =  (\frac{1}{5})   {}^{2} \: . \: m {}^{2 \: . \: 2}  \: . \: n {}^{2}

 =  \frac{1}{25} m {}^{4} n {}^{2}

G)

 = (0,5ab) {}^{2}

 = 0,5 {}^{2}  \: . \: a {}^{2} b {}^{2}

 =  \frac{1 {}^{2} }{2 {}^{2} }  \: . \: a {}^{2} b {}^{2}

 = ( \frac{1}{2} ) {}^{2}  \: . \: a {}^{2} b {}^{2}

 =  \frac{1}{4} a {}^{2} b {}^{2}

H)

 = ( - am {}^{5} x {}^{3} ) {}^{4}

 = ( - a) {}^{4}  \: . \: (m {}^{5} ) {}^{4}  \: . \: (x {}^{3} ) {}^{4}

 = ( - a) {}^{4}  \: . \: m {}^{5 \: . \: 4}  \: . \: n {}^{3 \: . \: 4}

 = ( - a) {}^{4}  \: . \: m {}^{20}  \: . \: x {}^{12}

 = a {}^{4} m {}^{20} x {}^{12}

I)

 = ( \frac{2}{3} x {}^{3} y {}^{2} ) {}^{2}

 = ( \frac{2}{3} ) {}^{2}  \: . \: (x {}^{3} ) {}^{2}  \: . \: (y {}^{2}  ){}^{2}

 = \frac{2 {}^{2} }{3 {}^{2} }  \: . \: x {}^{3 \: . \: 2}  \: . \: y {}^{2 \: . \: 2}

 =  \frac{4}{9} x {}^{6} y {}^{4}

J)

 = (a {}^{2} c {}^{3} ) {}^{7}

 = (a {}^{2} ) {}^{7}  \: . \: (c {}^{3} ) {}^{7}

 = a {}^{2 \: . \: 7}  \: . \: c {}^{3 \: . \: 7}

 = a {}^{14} c {}^{21}

Att. Makaveli1996

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