Question

Sendo A= √16²+273 e B=√97+192, calcule √(A-B) -2

Answer 1

$a = \sqrt{16^{2} + 273} \\ a = \sqrt{256 + 273} \\a = \sqrt{529} \\a = 23 \\ \\ b = \sqrt{97 + 192} \\ b = \sqrt{289} \\ b = 17$

$\sqrt{a - b - 2} \\ = \sqrt{23 - 17 - 2} \\ = \sqrt{4} \\ = 2$