Question

me ajudar ai por favor​

Answer 1

${x}^{2} - 25 = 0$

${x}^{2} = 25$

$x = \sqrt{25}$

$x = + ou - 5$

${x}^{2} - 64 = 0$

${x }^{2} = 64$

$x = \sqrt{64}$

$x = + ou - 8$

$8 {x}^{2} - 49 = 0$

$8 {x}^{2} = 49$

${x}^{2} = \frac{49}{8}$

${x}^{} = \sqrt{ \frac{49}{8} }$

$x = 7. \sqrt{ \frac{1}{8} }$

$9 { x}^{2} - 1 = 0$

$9 {x}^{2} = 1$

${x}^{2} = \frac{1}{9}$

$x = \sqrt{ \frac{1}{9} }$

$x = \frac{1}{3}$

${x}^{2} - 4 = (x + 2)(x - 2)$

${a}^{2} - 36 = (a + 6).(a - 6)$

${y}^{2} - 1 = (y + 1).(y - 1)$

$25 {x}^{2} - 4 = (5x + 2).(5x - 2)$

Espero ter ajudado

Answer 2

−25=0

{x}^{2} = 25x

2

=25

x = \sqrt{25}x=

25

x = + ou - 5x=+ou−5

{x}^{2} - 64 = 0x

2

−64=0

{x }^{2} = 64x

2

=64

x = \sqrt{64}x=

64

x = + ou - 8x=+ou−8

8 {x}^{2} - 49 = 08x

2

−49=0

8 {x}^{2} = 498x

2

=49

{x}^{2} = \frac{49}{8}x

2

=

8

49

{x}^{} = \sqrt{ \frac{49}{8} }x

=

8

49

x = 7. \sqrt{ \frac{1}{8} }x=7.

8

1

9 { x}^{2} - 1 = 09x

2

−1=0

9 {x}^{2} = 19x

2

=1

{x}^{2} = \frac{1}{9}x

2

=

9

1

x = \sqrt{ \frac{1}{9} }x=

9

1

x = \frac{1}{3}x=

3

1

{x}^{2} - 4 = (x + 2)(x - 2)x

2

−4=(x+2)(x−2)

{a}^{2} - 36 = (a + 6).(a - 6)a

2

−36=(a+6).(a−6)

{y}^{2} - 1 = (y + 1).(y - 1)y

2

−1=(y+1).(y−1)

25 {x}^{2} - 4 = (5x + 2).(5x - 2)25x

2

−4=(5x+2).(5x−2)

ESPERO TER AJUDADO