Question

f (x) =x elevado a dois +2x+1​

Answer 1

Resposta:

$\sf f(x) = x^{2} +2x +1$

$\sf f(x) = 0$

Resolvendo:

$\sf x^{2} +2x + 1 = 0$

$\sf x = \dfrac{-\,b \pm \sqrt{b^{2} -\, 4ac } }{2a} = \dfrac{-\,2 \pm \sqrt{2^{2} -\, 4\times 1 \times 1} }{2\times 1} = \dfrac{-\,2 \pm \sqrt{4 -\, 4} }{2}$

$\sf x = \dfrac{-\,2 \pm \sqrt{0} }{2} = \dfrac{-\,2 \pm 0 }{2}$

$\sf x_1= x_2 = \dfrac{-\,2 + 0 }{2} = - \dfrac{ 2 }{2} = - 1$

$\sf \LARGE S = \left\{ - 1 \right\}$

Explicação passo-a-passo: