Question

3.[1 1/3-(1/2-1/4).(1/3+3. 1/2)]

Answer 1

Explicação passo-a-passo:

$\sf 3\cdot\left[1~\dfrac{1}{3}-\left(\dfrac{1}{2}-\dfrac{1}{4}\right)\cdot\left(\dfrac{1}{3}+3\cdot\dfrac{1}{2}\right)\right]$

$\sf =3\cdot\left[\dfrac{3+1}{3}-\left(\dfrac{2-1}{4}\right)\cdot\left(\dfrac{1}{3}+\dfrac{3}{2}\right)\right]$

$\sf =3\cdot\left[\dfrac{4}{3}-\dfrac{1}{4}\cdot\left(\dfrac{2+9}{6}\right)\right]$

$\sf =3\cdot\left[\dfrac{4}{3}-\dfrac{1}{4}\cdot\dfrac{11}{6}\right]$

$\sf =3\cdot\left[\dfrac{4}{3}-\dfrac{11}{24}\right]$

$\sf =3\cdot\left[\dfrac{32-11}{24}\right]$

$\sf =3\cdot\dfrac{21}{24}$

$\sf =\dfrac{63}{24}$

$\sf =\dfrac{21}{8}$

Answer 2

Oie, Td Bom?!

= 3[1 1/3 - (1/2 - 1/4) . (1/3 + 3 . 1/2)]

= 3[3+1/3 - (2-1/4) . (1/3 + 3/2)]

= 3[4/3 - 1/4 . 11/6]

= 3[4/3 - 1.11/4.6]

= 3[4/3 - 11/24]

= 3[32-11/14]

= 3 . 21/24

= 3 . 21÷3/24÷3

= 3 . 7/8

= 3/1 . 7/8

= 3.7/1.8

= 21/8

Att. Makaveli1996