Respostas
respondido por:
1
Resposta:
(2+3i) × ( 1- 5i)= ( [2×1+ 2× ( - 5i)]) ×( [ 3i ×1] -[(3i× [-5i])
(2 -10i) × ( 3i) - ( 15 i*2)
( 2-10i) × (3i) - ( 15 [ -1])
( 6i- 30i*2) - ( -15)
( 6i- 30 [ -1)- (-15)
(6i+ 30+ 15)
z×w= 45+ 6i
Perguntas similares
5 anos atrás