Question

resolva 9^x+3^4x-1 -6=0

Answer 1

Ola Lulu

9^x + 3^(4x-1) - 6 = 0

3^2x + 3^4x/3 - 6 = 0

3^4x + 3*3^2x - 18 = 0

(3^2x - 3)*(3^2x + 6) = 0

3^2x = 3^1

2x = 1

x = 1/2

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