Question

Calcule o valor de x nas figuras A e B

Answer 1

Explicação passo-a-passo:

Pelo Teorema de Pitágoras:

a)

$\sf (2x)^2=x^2+(3\sqrt{3})^2$

$\sf 4x^2=x^2+9\cdot3$

$\sf 4x^2=x^2+27$

$\sf 4x^2-x^2=27$

$\sf 3x^2=27$

$\sf x^2=\dfrac{27}{3}$

$\sf x^2=9$

$\sf x=\sqrt{9}$

$\sf \red{x=3}$

b)

$\sf x^2+(11-8)^2=5^2$

$\sf x^2+3^2=25$

$\sf x^2+9=25$

$\sf x^2=25-9$

$\sf x^2=16$

$\sf x=\sqrt{16}$

$\sf \red{x=4}$