Question

resolva as inadequações, sendoU=R
OBS:resolver as letras D, E, F

Answer 1

$d)~~ \dfrac{a}{2} +1 \leq \dfrac{a}{3} \to ~~mmc=6\\\\ 3a+6 \leq 2a\to \\\\ 3a-2a \leq -6\to \\\\ \boxed{a \leq -6}\\\\\\\\ \boxed{S\{x \epsilon \mathbb{R}~ |~a \leq -6}$




$e)~~- \dfrac{y}{4} + \dfrac{1}{2} \geq 3- \dfrac{3y}{4} \to ~~mmc=4\\\\ -y+2 \geq 12-3y\to\\\\ -y+3y \geq 12-2\to \\\\ 2y \geq 10\to \\\\ y \geq \dfrac{10}{2} \\\\y \geq 5\\\\\\\\ \boxed{S\{x \epsilon \mathbb{R}~ |~y \geq 5}$




$f)~~2(x+1)- \dfrac{x-2}{4} \ \textless \ x\to \\\\ 2x+2- \dfrac{x-2}{4} \ \textless \ x\to ~~ mmc=4\\\\ 8x+8-(x-8)\ \textless \ 4x\to \\\\ 8x+8-x+8\ \textless \ 4x\to \\\\ 8x-x-4x\ \textless \ -8-8\to \\\\ 3x\ \textless \ -16\to \\\\ x\ \textless \ - \dfrac{16}{3} \\\\\\\\\boxed{S\{x \epsilon \mathbb{R}~ |~x\ \textless \ - \dfrac{16}{3} }$