• Matéria: Matemática
  • Autor: giioovaana2014osolo1
  • Perguntado 6 anos atrás

Calcule o que se pede abaixo:

Anexos:

Respostas

respondido por: CyberKirito
2

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A reta passa pelos pontos A(-3-4) e B(3,0)

EGR

\begin{vmatrix}-3&4&1\\3&0&1\\x&y&1\end{vmatrix}=0

\sf{-3(0-y)+4(3-x)+1(3y-0)=0}\\\sf{3y+12-4x+3y=0}\\\sf{-4x+6y+12=0\div(-2)}\\\huge\boxed{\boxed{\boxed{\boxed{\sf{2x-3y-6=0}}}}}

ERR:

\sf{2x-3y-6=0}\\\sf{3y=2x-6}\\\huge\boxed{\boxed{\boxed{\boxed{\sf{y=\dfrac{2x-6}{3}}}}}}

ESR:

\sf{2x-3y-6=0\implies 2x-3y=6}\\\sf{\dfrac{2x}{6}-\dfrac{3y}{6}=\dfrac{6}{6}}\\\huge\boxed{\boxed{\boxed{\boxed{\sf{\dfrac{x}{3}-\dfrac{y}{2}=1}}}}}

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