Question

Dado o triângulo retângulo ABC, o valor de x + y é: *

Answer 1

Resposta:

$\sf \sin{30^\circ} = \dfrac{Cateto \; Oposto }{Hipotenusa}$

$\sf \dfrac{1}{2} = \dfrac{x}{10}$

$\sf 2x = 10$

$\sf x = \dfrac{10}{2}$

$\framebox {\sf x= 5}$

$\sf \cos{30^\circ} = \dfrac{Cateto \; Adjacente }{Hipotenusa}$

$\sf \dfrac{\sqrt{3} }{2} = \dfrac{y}{10}$

$\sf 2y = 10\sqrt{3}$

$\sf y = \dfrac{10\sqrt{3} }{2}$

$\boxed {\sf y =5\sqrt{3} }$

Calcular o valor de x + y:

$\sf x + y = 5 + 5\sqrt{3} = \boxed{ \sf 5(1 + \sqrt{3} )}$

Explicação passo-a-passo: