Question

ALGUÉM ME AJUDA log 12(x2-x)=1 Ajuda

Answer 1

log 12 (x²-x)=1

(x²-x) = 12¹

x² -x - 12 = 0

∆ = (-1)² -4.1.(-12)= 1 +48= 49 =>√∆=7

x = -b±√∆/2a

x = 1±7/2.1

x' = 1+7/2 = 8/2 = 4 ✓

x" = 1-7/2 = -6/2 = -3 ✓