Question

Me ajudemmmmmmmmmmmmmmmmmmmmmmmmmm

Answer 1

Resposta:

1) $(a+4)^2=a^2+8a+16$

2) $\dfrac{4a^3+64a}{4a}=\dfrac{1}{4}(4a^3+64a)a^{-1}$

3) $\dfrac{4a^3+32a^2+64a-(4a^3+64a)}{4a}=\\\dfrac{4a^3-4a^3+32a^2+64a-64a}{4a}=\\\dfrac{32a^2}{4a}=\boxed{8a}$)

Explicação passo-a-passo: