Question

Resolva as equações do 2° grau usando a fórmula de bhaskara :

a) x² + x - 6 = 0


b)2x² – 9x + 4 = 0


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Answer 1

Resposta:

a) X1 = 2 , X2 = -3

b) X1 = 4 , X2 = 1/2

espero ter ajudado

Explicação passo-a-passo:

a)

$x=\frac{-1 +/-\sqrt{1^{2}-4.1.(-6) } }{2.1}$

$x=\frac{-1+/-\sqrt{1+24} }{2}$

$x=\frac{-1+/-\sqrt{25} }{2}$

$x=\frac{-1+/-5}{2}$

$x_{1} =\frac{-1+5}{2} \\\\x_{2}=\frac{-1-5}{2}$

$\left \{ {{x_{1} =2} \atop {x_{2} =-3}} \right.$

b)

$x=\frac{-(-9)+/-\sqrt{(-9)^{2}-4.2.4 } }{2.2}$

$x=\frac{9+/-\sqrt{81-32} }{4}$

$x=\frac{9+/-\sqrt{49} }{4}$

$x=\frac{9+/-7}{4}$

$\left \{ {{x_{1} =\frac{9+7}{4} } \atop {x_{2} =\frac{9-7}{4} }} \right.$

$\left \{ {{x_{1} =4} \atop {x_{2} =\frac{1}{2} }} \right.$