Question

1) Sabendo que log 2 = 0,301 ; log 3 = 0,477 ; log 5 = 0,699 e log 7 = 0,845, determine: a) log 6 = b) log 10 = c) log 144 = d) log 2,5 = 15 e) log 14= f) log 840 =

Answer 1

Explicação passo-a-passo:

log 6= log (2.3) = log2 + log 3= 0,301 + 0,477= 0,778

log 10=lg(2.5) =log2+log5=0,301 +0,699 = 1

$log144 = log{12}^{2} = 2.log 12 = 2.log(2.2.3) = 2.(0.301) + (0.301) + (0.477) = 2.158$

$log \frac{5}{2} = log5 \: - log2 \: = (0.699) - (0.301) = 0.398$