Question

ALGUÉM ME AJUDA PFVVVVVV! É para hoje!!! Rápido

Answer 1

Tendo em mente que $\log_ab=y$ pode ser escrito como $x^y=b$

$\log_3(7x-1)=3\\\\3^3=7x-1\\\\27=7x-1\\\\28=7x\\\\x=4\\\\\\\log_2(y^3+3)=7\\\\2^7=y^3+3\\\\128=y^3+3\\\\125=y^3\\\\y=\sqrt[3]{125}\\\\ y=5\\\\\\\log_y(x^2+9)=z\\\\\log_5(4^2+9)=z\\\\\log_5(16+9)=z\\\\\log_525=z\\\\5^z=25\\\\5^z=5^2\\\\z=2$