• Matéria: Matemática
  • Autor: fireblack124578
  • Perguntado 5 anos atrás

preciso pra hoje por favor​

Anexos:

Respostas

respondido por: Anônimo
1

Explicação passo-a-passo:

a) \sf \dfrac{7}{2}=\dfrac{6+1}{2}=\dfrac{6}{2}+\dfrac{1}{2}=\red{3~\dfrac{1}{2}}

b) \sf \dfrac{5}{3}=\dfrac{3+2}{3}=\dfrac{3}{3}+\dfrac{2}{3}=\red{1~\dfrac{2}{3}}

c) \sf \dfrac{8}{3}=\dfrac{6+2}{3}=\dfrac{6}{3}+\dfrac{2}{3}=\red{2~\dfrac{2}{3}}

d) \sf \dfrac{4}{3}=\dfrac{3+1}{3}=\dfrac{3}{3}+\dfrac{1}{3}=\red{1~\dfrac{1}{3}}

e) \sf \dfrac{8}{7}=\dfrac{7+1}{7}=\dfrac{7}{7}+\dfrac{1}{7}=\red{1~\dfrac{1}{7}}

f) \sf \dfrac{19}{3}=\dfrac{18+1}{3}=\dfrac{18}{3}+\dfrac{1}{3}=\red{6~\dfrac{1}{3}}

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